Out of 1900 km . Vishal travelled some distance by bus and some by aeroplane . Bus travels with average speed 60km/ hr and the average speed 700km/ hr . It takes 5 hrs to complete the journey . Find the distance , vishal travelled by bus ? (Please solve both equations obtained by this example )
Answers
Answered by
6
Solution:-
given,
let, travelled by bus = xkm
total distance = 1900km
travelled by airoplane = (1900-x)
total time = 5hours
bus speed = 60km/h
airoplane speed = 700km/h
time travelled by airoplane =(1900-x)/700
total time = x/60+(1900-x)/700
x/60-x/700 + 1900/700 = 5
(35x-3x)/2100 = 5-19/7
32x = 2100×(35-19)/7
32x = 300×16
x = 4800/32
x = 150
travelled by bus = 150km (ans)
given,
let, travelled by bus = xkm
total distance = 1900km
travelled by airoplane = (1900-x)
total time = 5hours
bus speed = 60km/h
airoplane speed = 700km/h
time travelled by airoplane =(1900-x)/700
total time = x/60+(1900-x)/700
x/60-x/700 + 1900/700 = 5
(35x-3x)/2100 = 5-19/7
32x = 2100×(35-19)/7
32x = 300×16
x = 4800/32
x = 150
travelled by bus = 150km (ans)
Answered by
0
Given:
Total distance = 1900 km
Distance by bus = bus km
Distance by airplane = ( 1900 - bus ) km
Total time = 5 hrs
Speed of the bus = 60 km / hr
Speed of the airplane = 700 km / hr
To find:
The distance traveled by bus.
Solution:
Time traveled in bus = Bus / 60
Time traveled in airplane = ( 1900 - bus ) / 700
Total time = Time traveled in bus + Time traveled in airplane
Total time = Bus / 60 + ( 1900 - Bus ) / 700
Substituting,
Bus / 60 - Bus / 700 + 1900 / 700 = 5
( 35 * Bus - 3 * Bus ) / 2100 = 5 - 19 / 7
32 * Bus = 2100 * ( 35 - 19 ) / 7
32 * Bus = 300 * 16
Bus = 4800 / 32
Hence,
Bus = 150 km
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