Question

Out of 1900km vishal travelled some distance by bus and se by aeroplane bus travels with average speed 60kmper hour and average speed of aeroplane is 700kmper hour it takes 5 hour to complete

Answer 1

Let Vishal travelled x km distance by bus and (1900 - x) km distance by aeroplane.

speed of bus = 60 km/h
speed of aeroplane = 700 km/h
total time taken to complete = 5 hrs

∵ time = distance/speed
∴ total time taken to complete = time taken to travel by bus + time taken to travel by aeroplane
⇒ 5hrs = x/60 + (1900 - x)/700
⇒5 = (70x + 1900 × 6 - 6x)/4200
⇒5 = (64x + 11400)/4200
⇒5 × 4200 = 64x + 11400
⇒21000 = 64x + 11400
⇒21000 - 11400 = 64x
⇒9600 = 64x
⇒x = 150 km

Hence, distance travelled by bus = 150 km
and distance travelled by aeroplane = 1900 - 150 = 1750 km

Answer 2

Given:

Total distance = 1900 km

Distance by bus = bus km

Distance by airplane = ( 1900 - bus ) km

Total time = 5 hrs

Speed of the bus = 60 km / hr

Speed of the airplane = 700 km / hr

To find:

The distance traveled by bus.

Solution:

Time traveled in bus = Bus / 60  

Time traveled in airplane = ( 1900 - bus ) / 700

Total time = Time traveled in bus + Time traveled in airplane

Total time = Bus / 60 + ( 1900 - Bus ) / 700

Substituting,

Bus / 60 - Bus / 700 + 1900 / 700 = 5

( 35 * Bus - 3 * Bus ) / 2100 = 5 - 19 / 7

32 * Bus = 2100 * ( 35 - 19 ) / 7

32 * Bus = 300 * 16

Bus = 4800 / 32

Hence,

Bus = 150 km

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