Out of 1900km,vishal travelled some distance by bus and some by aeroplane.bus travels with average speed 60 km/hr and average speed of aeroplane is 700 km/hr.its takes 5 hour to complete the journey .find the distance,vishal travelled by bus.
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Here is the answer---
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Let the distance covered by the Vishal from the Bus be x km.
Thus, Distance covered by the Vishal by the Aeroplane is (1900 - x)km.
For the Bus journey,
Average Speed = 60 km/hr.
Distance = x km.
Using the Formula,
⇒ Speed = Distance/Time
60 = x/Time
Time(T₁) = x/60 hr.
For the Aeroplane Journey,
Distance = (1900 - x) km.
Average Speed = 700 km/hr.
Thus, Time(T₂) = (1900 - x)/700 hr.
As per as the Questions,
T₁ + T₂ = 5 hours.
⇒ x/60 + (1900 - x)/700 = 5
⇒ [700x + 60(1900 - x)]/42000 = 5
⇒ 700x + 114000 - 60x = 42000 × 5
⇒ 640x = 210000 - 114000
⇒ 640x = 96000
⇒ x = 96000/640
⇒ x = 150 km.
Thus, the distance traveled by the Vishal from the bus is 150 km.
Distance traveled by the Vishal from the Aeroplane = 1900 - x
= 1900 - 150
= 1750 km.
→→→→→→→→→
Hope it helps.
Have a Nice day.
Here is the answer---
→→→→→→→→→
Let the distance covered by the Vishal from the Bus be x km.
Thus, Distance covered by the Vishal by the Aeroplane is (1900 - x)km.
For the Bus journey,
Average Speed = 60 km/hr.
Distance = x km.
Using the Formula,
⇒ Speed = Distance/Time
60 = x/Time
Time(T₁) = x/60 hr.
For the Aeroplane Journey,
Distance = (1900 - x) km.
Average Speed = 700 km/hr.
Thus, Time(T₂) = (1900 - x)/700 hr.
As per as the Questions,
T₁ + T₂ = 5 hours.
⇒ x/60 + (1900 - x)/700 = 5
⇒ [700x + 60(1900 - x)]/42000 = 5
⇒ 700x + 114000 - 60x = 42000 × 5
⇒ 640x = 210000 - 114000
⇒ 640x = 96000
⇒ x = 96000/640
⇒ x = 150 km.
Thus, the distance traveled by the Vishal from the bus is 150 km.
Distance traveled by the Vishal from the Aeroplane = 1900 - x
= 1900 - 150
= 1750 km.
→→→→→→→→→
Hope it helps.
Have a Nice day.
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