Physics, asked by Rimmyy242, 1 year ago

Out of 1900km,vishal travelled some distance by bus and some by aeroplane.bus travels with average speed 60 km/hr and average speed of aeroplane is 700 km/hr.its takes 5 hour to complete the journey .find the distance,vishal travelled by bus.

Answers

Answered by tiwaavi
8
Hello Dear.

Here is the answer---


→→→→→→→→→

Let the distance covered by the Vishal from the Bus be x km.
Thus, Distance covered by the Vishal by the Aeroplane is (1900 - x)km.


For the Bus journey,

 Average Speed = 60 km/hr.
    Distance =  x km.

Using the Formula,

             ⇒ Speed = Distance/Time
                       60 = x/Time
             Time(T₁) = x/60 hr.


For the Aeroplane Journey,

  Distance = (1900 - x) km.
Average Speed = 700 km/hr.

Thus, Time(T₂) = (1900 - x)/700 hr.


As per as the Questions,

               T₁ + T₂ = 5 hours.
     ⇒ x/60 + (1900 - x)/700 = 5
    ⇒ [700x + 60(1900 - x)]/42000 = 5
    ⇒  700x + 114000 - 60x = 42000 × 5
    ⇒ 640x = 210000 - 114000
    ⇒ 640x = 96000
   ⇒ x = 96000/640
   ⇒ x = 150 km.


Thus, the distance traveled by the Vishal from the bus is 150 km.

Distance traveled by the Vishal from the Aeroplane = 1900 - x
                                                                                  = 1900 - 150
                                                                                  = 1750 km.


→→→→→→→→→


Hope it helps.


Have a Nice day.
Similar questions