Question

Out of 200 bulbs in a box, 12 bulbs are defective. One bulb is taken out at
random from the box. What is the probability that the drawn bulb is not defective?

Answer 1

total nos. of bulbs=200
total nos. of defective bulbs=12
so,total no. of non defective bulbs=200-12=188 bulbs

hence ,probability of drawing a non defective bulb=(nos. of non-defective bulbs)/(total nos. of bulbs)

=188/200
=0.94

Answer 2

P(not defective)=188÷200=0.94