Out of 200 bulbs in a box, 12 bulbs are defective. One bulb is taken out at
random from the box. What is the probability that the drawn bulb is not defective?
Answers
Answered by
39
total nos. of bulbs=200
total nos. of defective bulbs=12
so,total no. of non defective bulbs=200-12=188 bulbs
hence ,probability of drawing a non defective bulb=(nos. of non-defective bulbs)/(total nos. of bulbs)
=188/200
=0.94
total nos. of defective bulbs=12
so,total no. of non defective bulbs=200-12=188 bulbs
hence ,probability of drawing a non defective bulb=(nos. of non-defective bulbs)/(total nos. of bulbs)
=188/200
=0.94
desiree1963:
thank you so much Faisal07 yes 47/50
most welcome :)
Answered by
8
P(not defective)=188÷200=0.94
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