Out of 200 bulns in a box ,12 bulbs are defective one bulb is taken out at random from the box.what is the probability that the drawn bulb is not defective
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Answered by
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Total no. of bulbs in the box=200
no. of defective bulbs=12
no. of favoutable outcomes=200-12=188
probability of the event=188/200=47/50
HOPE IT HELPS YOU.
no. of defective bulbs=12
no. of favoutable outcomes=200-12=188
probability of the event=188/200=47/50
HOPE IT HELPS YOU.
Answered by
1
According to the Question :-
Total no. of cases = 200
Favourable cases => 200 – 12 = 188
Required probability = ![\bf\huge\frac{188}{200} \bf\huge\frac{188}{200}](https://tex.z-dn.net/?f=%5Cbf%5Chuge%5Cfrac%7B188%7D%7B200%7D)
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