Math, asked by ponnua6529, 11 months ago

Out of 200 fish in an aquarium 99%are red how many red mustbe removed in ordee to reduce the percentage of red fish to 98%

Answers

Answered by magician007
0

Answer:

This is very easy question you have just to make equation than it will be solved easily. Number of red fish = 99% of 200 = 198. Let the number of red fish removed be x. 198 - x = 98% of 200 - x

⇒198−x=98/100∗200−x

⇒19800−100x=19600−98x

⇒19800−19600=100x−98x

⇒200=2x⇒x=100

So, we have to remove 100 red fish so the number of red fish in total become 98%. It is quit unbelievable answer, the difference of percentage is 1 but the difference in number is 100. Ask this question to your friend and see how they are struggling to get the answer and also not believe when they got the right answer.

Step-by-step explanation:

Answered by AditiChaurasiya
0

Answer:

red fishes = 99percent

1 percent =2 fishes 99percent=99×2=198 we need to remove 2 fishes from the aquarium so that 198-2 =196

196÷2=98 percent

Answer = 2 fishes

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