Question

Out of 200 students in a class, 120 passed in Physics, 140 in Mathematics, 40 failed in both
subjects, then number of students passed in both is
(A) 100
(B) 160
(C) 180
(D) 240​

Answer 1

Answer:

160

Step-by-step explanation:

total passed in both = total-total fail in both

= 200-40=160

Answer 2

Concept Introduction:

In a class total students appeared in maths and physics exam some failed in one subject and some failed in both the subjects and some passed in both the subjects.

Given: Out of $200$ students in a class, $120$ passed in Physics, $140$ in Mathematics, $40$ failed in both subjects.

To Find:

We have to find the value of, number of students passed in both the subjects.

Solution:

According to the problem,

Let, number of students passed in both be x.

Total number of students = Number of students passed in physics + Number of students passed in maths - Number of students passed in both + number of students failed in both.

⇒$200=120+140-x+40$

⇒$x=120+140+40-200=100$

Final Answer:

The value of number of students passed in both subjects are $100$.

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