Question

out of 2000 employees in an office 48% preferred Coffee (c), 54% liked (T), 64% used to
smoke (S). Out of the total 28% used C and T, 32% used T and S and 30% preferred C and S,
only 6% did none of these. The number having all the three is​

Answer 1

Total = 2000 = 100 %

C = 48 %

T = 54 %

S = 64 %

C ∩ T = 28 %

T ∩ S = 32%

C ∩ S = 30 %

Having all three = C ∩ T ∩ S = ?

None = 6 %

Total = C + T + S - C ∩ T - T ∩ S - C ∩ S + C ∩ T ∩ S + None

=> 100 = 48 + 54 + 64 - 28 - 32 - 30 + C ∩ T ∩ S + 6

=> C ∩ T ∩ S = 18 %

18 % of 2000 = (18/100) * 2000 = 360

360 having all the three

Answer 2

Answer:

360

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