Out of 2p and 3s which has larger energy
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The energy concept of above orbitals are in accordance with n+l rule. Whichever orbital will have greater n+l value will have larger energy.
2p has 2+1 = 3
3s has 3+0 =3
As the above has same no. of n+l value then energy level will be determined by the value of n. If value of n is smaller then it will be filled first and also it less energy than upcoming orbitals.
Therefore 3s has larger energy than 2p.
Hope you get your answer
2p has 2+1 = 3
3s has 3+0 =3
As the above has same no. of n+l value then energy level will be determined by the value of n. If value of n is smaller then it will be filled first and also it less energy than upcoming orbitals.
Therefore 3s has larger energy than 2p.
Hope you get your answer
Answered by
6
°°°QUANTUM NUMBER•••
BOHR-BURY RULE (n+l)
in a multi electron atom the energy of an electron depends upon the value of principal quantum number and azimuthal quantum number.
the relative order of energies of various sub shell in a multi electron atom can be predicted with the help of n+l rule or bohr bury rule!!
For 2p, n+l= 2+1= 3
For 3s, n+l = 3+0 = 3
both have same energies
now we have look the value of n higher the value of principal quantum number higher the energy of the shell
Hence, energy of 3s is greater than 2p
BOHR-BURY RULE (n+l)
in a multi electron atom the energy of an electron depends upon the value of principal quantum number and azimuthal quantum number.
the relative order of energies of various sub shell in a multi electron atom can be predicted with the help of n+l rule or bohr bury rule!!
For 2p, n+l= 2+1= 3
For 3s, n+l = 3+0 = 3
both have same energies
now we have look the value of n higher the value of principal quantum number higher the energy of the shell
Hence, energy of 3s is greater than 2p
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