Math, asked by isratjahaan121, 1 month ago

out of 300 companies, the companies who use different media advertisements are as follows,N=200,R=100,T=80.N intersection R=50,R intersection T=30,T intersection N=50 and N intersection R intersection intersection T =50.find the number of companies who uses other media excepting newspaper, radio,television for advertisements​

Answers

Answered by shashisubashi1985
0

j. hfu. light

Answered by amitabiswal98
0

Answer:

Newspaper n( N )=200

Radio n(R)=100

Television n(T)=40

Newspaper and Radio= n(NR)=50

Radio and television = n(RT)=20

newspaper and Television = n(NT)=25

Newspaper, radio and television=n(NRT)=5

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★ Using relation

N(N U E U T)=n(N)+n(R)+n(T)- n(N ∩ R)-n(R ∩ T)-n(N ∩ T)-n(N ∩ R ∩ T)

putting the values In the Formula

n(N ∩ R ∩ T) = 200+100+40-50-20-25+5

n(N ∩ R ∩ T) = 345-95

n(N ∩ R ∩ T) = 250

USING MEDIA BY COMPANIES= 250

NOW,

number of company none using media=

Total companies - no. of using media

→ 300 - 250

→ 50

Hence,

None using media by company is 50

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