out of 3500 condidates who appeared for an examination 90%got passed how many conditates got passed
Answers
Let Z be the number
Z = 13x + 11 where x is the quotient when Z is divided by 13
Z = 17y + 9 where y is the quotient when Z is divided by 17
13x + 11 = 17y + 9
13x + 2 = 17y since x and y are quotients they should be whole numbers . Since y has to be a whole number the left hand side should be multiple of 17
The least possible value of x satisfying the condition is 9 and y will be 7
The answer is 13*9 + 11 = 128 or it is 17*7 + 9 = 128
This is the least number possible. There will be multiple answers and will increase in multiples 17*13 = 221 like 349 , 570, etc.
hope that u r helpful
Step-by-step explanation:
please follow thank and brinlylist please
Given that,
- Total number of candidates = 3500
- Percentage of Passed candidates = 90%
- Number of Candidates Passed = ?
We know, 90% of Total candidates passed.
⇒ 90% of 3500 (% means /100 so, 90 % can be written as 90/100)
⇒ 90/100×3500
⇒ 3150.
∴ 3150 Candidates passed the examination.
Hope this helps you.
Thankyou for your question.
Mark me as Brainleist.