Question

out of 3d and 4s which is more n+1 value​

Answer 1

Answer:

We say that the 4s orbitals have a lower energy than the 3d, and so the 4s orbitals are filled first. ... The electrons lost first will come from the highest energy level, furthest from the influence of the nucleus. So the 4s orbital must have a higher energy than the 3d orbitals

Answer 2

To find:

Out of 3d and 4s which is more n+l value?

Calculation:

For 3d Orbital

Principal Quantum Number = n = 3

Azimuthal Quantum Number = l = 2

$\boxed{ \therefore \: n + l = 3 + 2 = 5}$

For 4s Orbital:

Principal Quantum Number = n = 4

Azimuthal Quantum Number = l = 0

$\boxed{ \therefore \: n + l = 4 + 0= 4}$

So, 3d orbital has a higher (n+l) value as compared to 4s. Hence 3d Orbital has higher energy content than 4s Orbital.