Out of 400 bulbs in a box 15 bulbs are defective one bulb is taken out at random from the box find the probability that the drawn bulb is not effective
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p(not defective bulb) is 77/80
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Answer:
Step-by-step explanation:
Total bulbs=400
Defective bulbs(not effective)=15
P(not effective)=15/400
=3/80
Hope it is helpful
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