Question

out of 48 students one third play cricket and basketball one fourth play cricket and football one sixth play football and basketball no student play only basketball number of students playing only cricket is double of students playing only football find fraction of students playing cricket​

Answer 1

Answer:

5/12

Step-by-step explanation:

1/3 = play   cricket and basketball

1/4 = play  cricket and football

1/6 =  play football and basketball

no student play basketball so 1/3 is first fraction of children play cricket.

number of students playing only cricket is double of students playing football so fraction will be 1/12

So

1/3+1/12=5/12

Answer 2

Answer:

36/48 or 37/48 or 38/48

Step-by-step explanation:

one third play cricket and basketball

C ∩ B = 48/3 = 16

one fourth play cricket and football

C ∩ F = 48/4 = 12

one sixth play football and basketball

F ∩ B = 48/6  = 8

no student play only basketball

=> Only Basket Ball = 0

Let say Only Playing FootBall = Y

then Oonly Paying Cricket = 2Y

Playing all three Games = X  = C ∩ F ∩ B

Assuming Playing Nome = 0

Total = Y + 2Y + 0  + (C ∩ B - C ∩ F ∩ B) + (C ∩ F - C ∩ F ∩ B) + (F ∩ B - C ∩ F ∩ B) + C ∩ F ∩ B  + Playing None

=> 48 = 3Y + (16-X) + (12 - X) + (8-X) + X + 0

=> 3Y - 2X = 12

if X = 0   Y = 4  ,

  X =  3   Y  = 6

 X  = 6   Y  = 8

Playing Cricket = 2Y + 16-X + 12-X + X

= 28 + 2Y - X

X = 0   Y = 4  

= 28 + 2*4 - 0  = 36

  X =  3   Y  = 6

= 28 + 2*6 - 3  = 37

 X  = 6   Y  = 8

= 28 + 2*8 - 6  = 38

Fraction of Students Playing Cricket = 36/48 or 37/48 or 38/48