Math, asked by Iqrakafeel3136, 11 months ago

Out of 50 consecutive natural numbers, two are chosen at random. What is the probability that the sum of the numbers is odd ?

Answers

Answered by sushant2586
3

Answer:

1/2

Step-by-step explanation:

In 50 consecutive natural numbers, there are always, 25 odd numbers and 25 even numbers.

∴ Probability of selecting one odd number P(o)= 1/2

Probability of selecting even number P(e) = 1/2

When 2 number are selected at random, to get the sum of the numbers odd, one number must be odd and the other even.

Probability of selecting 2nd odd number  number, when 1st is even = 1/2 × 1/2 = 1/4

Probability of selecting 2nd even number when the 1st is odd = 1/2 × 1/2 = 1/4

∴ total probaility = 1/4 + 1/4 = 1/2

∴ Probability that sum of the numbers is odd = 1/2


amitnrw: Please check my answer
Answered by amitnrw
7

Answer:

25/49

Step-by-step explanation:

Out of 50 consecutive natural numbers, two are chosen at random. What is the probability that the sum of the numbers is odd ?

50 consecutive natural number will have

25 odd number

25 even number

Even + odd = odd

odd + Even = Odd

Probability of selecting two events

= (25/50)(25/49)  + (25/50)(25/49)

= (25*25 + 25*25)(50*49)

= 25 /49

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