Out of 50 students in a class, 36 passed in Science, 25 passed in Mathematics, and 22 passed in both Science and Mathematics. How many students failed in both the subjects
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Let M= The set of students passed in Mathematics
S= The set of students passed in Science
Then, n(S)=28,n(M∩S)=10,n(M∪S)=50
We have n(M∪S)=n(M)+n(S)−n(M∩S)
50=n(M)+28−10
⇒n(M)=32
Aliter
From the Venn diagram
x+10+18=50
x=50−28=22
Number of students passed in Mathematics =x+10=22+10=32
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