Math, asked by kamaleshkannan2000, 1 year ago

out of 500 car owners investigated,400 owned car A and 200 owned car B,50 owned both A and B cars.is this data correct?

Answers

Answered by Brucklin
46
Thi data is not correct. As there are 500 cars as written the A and B cannot have 400,200 car each.

kamaleshkannan2000: solve me by letterings
Answered by nalinsingh
90

Hey !!

Let U be the set of car owners investigated. M be the set of persons who owned car A and S be the set of persons who owned car B.

Given that,

                 n (U) = 500 , n (M) = 400 , n (S) = 200 and n ( S ∩ M ) = 50

Then,

             n ( S ∪ M ) = n (S) + n (M) - n (S ∩ M) = 200 + 400 - 50 = 550

But S ∪ M ⊂ U implies n (S ∪ M) ≤ n (U).

This is a contradiction. So, the given data is incorrect.


GOOD LUCK !

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