Math, asked by msebastinmerline, 7 months ago

out of 500 cars owners investigation,400 owned car A and 200 owned car B,50 owned both A and B cars.is this data correct?​

Answers

Answered by khadija1212
1

Answer:

no.

Step-by-step explanation:

because there are only 500 cars but the statement says that there are 650 cars

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Answered by Anonymous
7

Answer:

Hey !!

Let U be the set of car owners investigated. M be the set of persons who owned car A and S be the set of persons who owned car B.

Given that,

                 n (U) = 500 , n (M) = 400 , n (S) = 200 and n ( S ∩ M ) = 50

Then,

             n ( S ∪ M ) = n (S) + n (M) - n (S ∩ M) = 200 + 400 - 50 = 550

But S ∪ M ⊂ U implies n (S ∪ M) ≤ n (U).

This is a contradiction. So, the given data is incorrect.

GOOD LUCK !

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