Out of 500 HIV patients in their AIDS stage, 325 were suffering from Tuberculosis, 230 were suffering from Diarrhea. If all the patients were suffering from at least one of them, find how many of them were suffering from at least one of them, find how many of them were suffering from both.
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Answer:
555, 55
Step-by-step explanation:
HIV patients = 500
Tuberculosis = 325
Diarrhea = 230
if each person was suffering from at least on of them then that means,
= (325 + 230) - 500
= 555 - 500
= 55 patients were suffering from both diseases and all the people ( 555 ) were suffering from at least 1 disease
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