Question

Out of 500 students,260 participated in the school Annual Day celebrations. Find the percentage of students who did not participate

with solution​

Answer 1

Answer:

$\purple{ \bold{ \boxed{48\%}}}$

Step-by-step explanation:

Given,

• Out of 500 students,260 participated in the school Annual Day celebrations.

To find,

• The percentage of students who did not participate.

Solution,

• Students didn't participated, (500-260) = 240.

According to the question,

$500 = 100\% \\ 1 = \frac{100}{500} \% \\ 240 = \frac{100 \times 240}{500}\% \\ = 48\%$

Hence, the percentage of unprecedented students are 48%

Answer 2

Step-by-step explanation:

Step-by-step explanation:

Given,

Out of 500 students,260 participated in the school Annual Day celebrations.

To find,

The percentage of students who did not participate.

Solution,

Students didn't participated, (500-260) = 240.

According to the question,

\begin{gathered}500 = 100\% \\ 1 = \frac{100}{500} \% \\ 240 = \frac{100 \times 240}{500}\% \\ = 48\%\end{gathered}

500=100%

1=

500

100

%

240=

500

100×240

%

=48%

Thank you I hope it will help you

Hence, the percentage of unprecedented students are 48%