Physics, asked by reenaageorge4335, 7 months ago

Out of 60 W and 40 W lamps, which one has higher electrical resistance when in use.

Answers

Answered by sambu22
6

Answer:

40W lamps have higher resistance

Explanation:

AS WE KNOW THAT POWER ISINVERSELY

PROPORTIONAL TO THE RESISTANCE OF THE WIRE..i.e.,

R=V/I and R=1÷A

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Answered by Anonymous
9

Answer:

Hence, the resistance of the bulb of 60W is greater.

Explanation:

Let the potential difference used by the bulbs be 'V' . And their usage of current be I.

Here the two bulbs are given.

Let us calculate the resistance of each of them separately.

(i) 60 W

Let the resistance of this bulb be R'.

Here, watt is the symbol of Power. Then,

Power = V × I

60W = VI

By ohm's law we know that,

R = V/I

V = IR

Here, its resistance = R'.

=> 60W = IR' × I

=> 60VI = IR' × I

=> 60V = IR'

=> 60× V/I = R'

=> 60R = R'

Hence, the resistance of this bulb = R' = 60R

(ii) 40 W

Let the resistance of this bulb be R".

Here, watt is the symbol of Power. Then,

Power = V × I

40W = VI

By ohm's law we know that,

R = V/I

V = IR

Here, its resistance = R'.

=> 40W = IR" × I

=> 40VI = IR" × I

=> 40V = IR"

=> 40× V/I = R"

=> 40R = R"

Hence, the resistance of this bulb = R" = 40R

On comparing both 60R and 40R, we get,

60R > 40R

Hence, the resistance of the bulb of 60W is greater.

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