Question

Out of 600 bulbs 12 are defective. One bulb is drawn at random then what is the probability that it is non defective bulb

Answer 1

Heya

Total outcomes = 600

Favourable outcomes of getting non - defective bulb = 600 - 12 = 588

P(x) = Favourable outcomes / Total outcomes

P(getting non - defective bulb) = 588/600

Hope this helps.

Answer 2

Hey,

There are total 600 bulbs and Out of 600 bulbs 12 are defective.

So there are total 588 non defective bulbs.

The Probability that the bulb is a non defective bulb is 0.98

$= \frac{588}{600} \\ = 0.98$

hope it helps u ^-^