Out of 60W and 40W lamps , which one has higher electrical resistance when in use. Give reason.
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Answers
Answer:
Hence, the resistance of the bulb of 60W is greater.
Explanation:
Let the potential difference used by the bulbs be 'V' . And their usage of current be I.
Here the two bulbs are given.
Let us calculate the resistance of each of them separately.
(i) 60 W
Let the resistance of this bulb be R'.
Here, watt is the symbol of Power. Then,
Power = V × I
60W = VI
By ohm's law we know that,
R = V/I
V = IR
Here, its resistance = R'.
=> 60W = IR' × I
=> 60VI = IR' × I
=> 60V = IR'
=> 60× V/I = R'
=> 60R = R'
Hence, the resistance of this bulb = R' = 60R
(ii) 40 W
Let the resistance of this bulb be R".
Here, watt is the symbol of Power. Then,
Power = V × I
40W = VI
By ohm's law we know that,
R = V/I
V = IR
Here, its resistance = R'.
=> 40W = IR" × I
=> 40VI = IR" × I
=> 40V = IR"
=> 40× V/I = R"
=> 40R = R"
Hence, the resistance of this bulb = R" = 40R
On comparing both 60R and 40R, we get,
60R > 40R
Hence, the resistance of the bulb of 60W is greater.