Math, asked by amarsingh930, 1 month ago

out of 65 people, 10 are from city a, 25 from city b and 30 from city c. what is the probability that a random person chosen is either from city b or c?

Answers

Answered by samuelmadrid
0

Answer:

84.7%

Step-by-step explanation:

city a = 15.4%

city b = 38.5%

city d 46.2%

Answered by niteshrajputs995
0

Answer:

Probability that a random person chosen is either from(B or C) = 0.846 or 84.6%

Step-by-step explanation:

There are 25+30 = 55 people who are either from city b or city c out of a total of 65 people. Therefore, the probability that a random person chosen is either from city b or c can be calculated as:

P(B or C) = Number of people from city B or C / Total number of people

P(B or C) = 55 / 65

P(B or C) = 0.846 or 84.6%

This means that there is an 84.6% chance that a random person chosen is either from city b or c. This probability can be interpreted as the likelihood of selecting a person from city b or c out of all possible choices.

The concept of probability is an important tool in statistics and mathematics, as it allows us to calculate the likelihood of various outcomes and make informed decisions based on the information available. In this case, understanding the probability of selecting a person from city b or c can help us make predictions about the demographics of a larger population or plan for events that are likely to draw a diverse crowd.

For more such question: https://brainly.in/question/32472945

#SPJ2

Similar questions