Question

out of 7 consonants and 4 vowels how many words with contain 3 consonants and 2 vowels can be formed​

Answer 1

Answer:

Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)

= (7C3 x 4C2)

= 7 x 6 x 5 x 4 x 3

3 x 2 x 1 2 x 1

= 210.

Number of groups, each having 3 consonants and 2 vowels = 210.

Each group contains 5 letters.

Number of ways of arranging

5 letters among themselves = 5!

= 5 x 4 x 3 x 2 x 1

= 120.

Answer 2

Answer:

Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed? [E]. = 210. Number of groups, each having 3 consonants and 2 vowels = 210.