Question

Out of 8 items that have arrived, one is defective. A worker picks these parts one by one. What is the probability that the third is defective given that the first two are not

Answer 1

Answer:

answer is one bro one bhai bhai

Answer 2

Given :- Out of 8 items that have arrived, one is defective. A worker picks these parts one by one. What is the probability that the third is defective given that the first two are not ?

Solution :-

we have,

→ Total items arrived = 8 .

→ No. of defective item = 1 .

now, given that,

• first 2 packed items are not defective .

then,

→ Items left to be packed = 8 - 2 = 6 items.

and,

→ Defective item is = 1 .

therefore,

→ Probability that the 3rd item is defective = (No. of Defective item) / (Items left to be packed) = (1/6) (Ans.)

Hence, probability that the third is defective will be (1/6).

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If a die is rolled twice, what is the probability that the sum of the points is more than 9

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