out of 80 children in the class 40% two friends and a subject that was to Sanskrit how many students choose friends and how much to Sanskri
Answers
Answer:
Let,
French = set A,
English = set B,
Sanskrit = set C
n(A)=17,n(B)=13,n(C)=15
n(A∩B)=9,n(B∩C)=4,n(A∩C)=5
n(A∩B∩C)=3
n(u)=50
n(A∩
B
ˉ
∩
C
ˉ
)=n(A)−n(A∩B)−n(A∩C)+n(A∩B∩C)
=17−9−5+3
French only =6
n(
A
ˉ
∩B∩
C
ˉ
)=n(B)−n(B∩C)−n(A∩B)+n(A∩B∩C)
=13−4−9+3
English only =3
n(
A
ˉ
∩
B
ˉ
∩C)=n(C)−n(A∩C)−n(B∩C)+n(A∩B∩C)
=15−4−5+3
Sanskrit only =9
n(
A
ˉ
∩B∩C)=n(B∩C)−n(A∩B∩C)
French, English and Sanskrit =4−3=1
n(A∩
B
ˉ
∩C)=n(A∩C)−n(A∩B∩C)=5−3=2
n(A∩B∩
C
ˉ
)=n(A∩B)−n(A∩B∩C)=9−3=6
n(name of A orB or C )=5a−(A∩B∩C)
=5a−{n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)}
=50−{17+13+15−9−4−5+3}
=20
∴n(at least of A or B or C)=50−20=30
Answer:
No one students choose French = 32
No of students choose Sanskrit = 48
total students = 80
percentage of French students = 40%
thus No of students choose French= 40/100×80=32
No of students choose sanskrit= 80-32=48