Out of 80 coins, one is counterfeit. What is the minimum number of weighing needed to find out the counterfeit coin?
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First we divide the 80 coins into two halves -----> 40+40 (step 1) so we will be weighing its weight so one set will have less weight then again same ----------------> 20+20 again (step 2) ----------------> 10+10 again (step 3) ----------------> 5+5 again (step 4) ----------------> 2+2+1 (step 5) weighing the two sets of two coins if they found equal the remained one is the required. else again------------------------->1+1 (step 6)then we will be getting. so minimum 5, max 6
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