Math, asked by smartygirl, 1 year ago

Out of 800 boys in a school, 224 played cricket, 240 played hockey and 336 played basketball.Of the total ,64 played both basketball and hockey , 80 played cricket and basketball and 40 played cricket and hockey; 24 played all the three games.Find
     i)how many played only only cricket,basketball and only cricket,only hockey,only basket ball?
    ii)how many played at least one game?
   iii)how many played only two games?
   iv)how many do not play any of the 3 games?

Answers

Answered by kvnmurty
102
See the Venn diagram enclosed.

Only cricket and basket ball = 80 - 24 = 56
only cricket and hockey = 40 - 24 = 16
only hockey and basket ball = 64 - 24 = 40

played only cricket = 224 - 56 - 24 - 16 = 128
only hockey = 240 - 16 - 24 - 40 = 160
only basketball = 336 - 56 -24 -40 = 216

Those who played no games = 800 - 336 - 128 -16 - 160 = 160

played at least one game = total - who played no game = 800 - 160 = 640

two games only = 56 + 16 + 40 = 112   (numbers calculated above)

no games = 160 - calculated above

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Answered by appleshivam123
26

In a college, out of 850 students, 230 play cricket; 250 hockey and 360 basketball. Of the total, if 75 play both basketball and hockey; 68 play cricket and basketball; 37 play cricket and hockey; and 30 play all the three games, how many students don't play any games at all?

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