Question

Out of 900 voters in an election, 22% voted for candidate A and the rest voted for candidate B.

Find by how many votes did candidate B win the election.

Answer 1

${\pmb{\underline{\sf{ Required \ Solution ... }}}}$

As We know that there are Total 900 voters in an election.

»Out of which 22% voted for Candidate A in an Election.

$\colon\implies{\sf{ 900 \times \dfrac{22}{100} }} \\ \\ \colon\implies{\sf{ 900 \times \dfrac{11}{50} }} \\ \\ \colon\implies{\sf{ 18 \times 11 }} \\ \\ \colon\implies{\sf{ 198 }}$

»» Out of the Total Votes of City, Rest are voted for the Candidate B in an Election.

›(100 - 22)% = 78%

Most of the votes Or More than the Half of the Votes were in Favour of the Candidate B in an Election.

$\colon\implies{\sf{ 900 \times \dfrac{78}{100} }} \\ \\ \colon\implies{\sf{ 9 \times 78 }} \\ \\ \colon\implies{\sf{ 702 \ votes }}$

Now, We've to find the difference of the votes delivered to both candidates in an Election.

$\colon\implies{\sf{ 702 - 198 }} \\ \\ \colon\implies{\sf{ 504 }}$

Hence,

»Candidate B won an Election by 504 votes that were the winning votes of the Candidate.