Question

Out of a certain dum of money a boy spends 3/5, and then 1/4 of the remainder. He has ₹ 15 left. How much amount had he first?​

Answer 1

Answer:

out of a certain sum of money a boy spends 3/5, abd then 1/4 of the remainder.he has Rs15 left.

amount he had he at first = Rs 50

Step-by-step explanation:

Let say boys has Money = Rs 20 M

Boy spends money = (3/5) * 20 M = 12M

Remainder Money  = 20M - 12M = 8M Rs

He spend then 1/4 of remainder

Further Spend = (1/4) 8M = 2M Rs

He left with MOney = 8M - 2M = 6M Rs

6M = 15

=> M = 2.5

20M = 20 * 2.5 = Rs 50

Answer 2

Answer.

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Step-by-step explanation:

Let the boy has x amount of money at first.

At first, he spends 3/5 of this amount

Amount spent = = (3/5)x

Amount remaining with him = x - (3/5)x

= (2/5)x

Then he spends 1/4th of remaining amount

Amount spent second time = (1/4) of (2/5) x

= (1/10) x

Amount remaining with him = (2/5)x

= (3/10) x

According to question, remaining amount = ₹ 15

Thus, (3/10) x = 15

⇒x= 50

Hence, amount available with boy at first = ₹50