out of a certain sum of money a boy spends 3/5, abd then 1/4 of the remainder.he has Rs15 left. how much amount had he at first?
Answers
Answer:
out of a certain sum of money a boy spends 3/5, abd then 1/4 of the remainder.he has Rs15 left.
amount he had he at first = Rs 50
Step-by-step explanation:
Let say boys has Money = Rs 20 M
Boy spends money = (3/5) * 20 M = 12M
Remainder Money = 20M - 12M = 8M Rs
He spend then 1/4 of remainder
Further Spend = (1/4) 8M = 2M Rs
He left with MOney = 8M - 2M = 6M Rs
6M = 15
=> M = 2.5
20M = 20 * 2.5 = Rs 50
He had Rs 50 amount at first
Answer:
Step-by-step explanation:
Let the boy has x amount of money at first.
At first, he spends 3/5 of this amount
Amount spent = = (3/5)x
Amount remaining with him = x - (3/5)x
= (2/5)x
Then he spends 1/4th of remaining amount
Amount spent second time = (1/4) of (2/5) x
= (1/10) x
Amount remaining with him = (2/5)x - (1/10)x
= (4/10)x - (1/10)x
= (3/10) x
According to question, remaining amount = ₹ 15
Thus, (3/10) x = 15
⇒x= 50
Hence, amount available with boy at first = ₹50