Math, asked by lakshayjain1701lj, 10 months ago

Out of a group of 50 persons, 32 take eggs, 25 take meat and 15 take both eggs and meat.

How many of them are pure vegetarians?​

Answers

Answered by Anonymous
18

Sets

Total number of persons in the group = 50

Number of persons who take eggs = n( E ) = 32

Number of persons who take meat = n( M ) = 25

Number of persons who take both eggs and meat = n( E ∩ M ) = 15

Number of persons who take eggs or meat [ i.e Number of non - vegetarians ] =  n( E ∪ M ) = ?

Using the relation between two sets we get,

⇒ n( E ∪ M ) = n( E ) + n ( M ) - n( M ∩ N )

Substituting the values we get,

⇒ n( E ∪ M ) = 32 + 25 - 15

⇒ n( E ∪ M ) = 57 - 15

⇒ n( E ∪ M ) = 42

∴ Total number of non - vegetarians = 42

Hence, Number of pure vegetarians = Total number of persons - Total number of non - vegetarians = 50 - 42 = 8

∴ there are 8 pure vegetarians in the given group of 50 persons.

Answered by Anonymous
14

: Given :

Egg = n(E)=32

meat = n(M)=25

Egg and meat =n(E ⋃ M)=15

Total person = 50

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★ To find,

Pure vegetarian=?

† Formula

n(E M)= n(E)+n(M)-n(E M)

Now,

n(E ⋃ M)= 32+25-15

n(E ⋃ M) = 57-15

n(E ⋃ M) = 42

for vegetarian= total person - non vegetarian

Vegetarian = 50-42

vegetarian = 8

Hence,

in 50 person their are 8 vegetarian person and remaining 42 are non vegetarian.

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