Out of a total of 10 students, the average weight of 9 students is 60 kg. If the Weight of the 10”‘ student is 9 kg more than the average weight of all the 10 students, then the weight of 10”‘ student would be :
Answers
Step-by-step explanation:
Average = sum/number *of quantities.
Here,
=> Average weight = (sum of weight of 9 sts)/9
=> 60 = (sum of weight of 9 students)/9
=> 540 = sum of weight of 9 students
Let the average weight of 10 students be 'a'.
So, as said,
Weight 10th student = a + 9
Thus,
=> average weight of 10 students = a
=> (weight of 9 students + 10th stude.) = a
=> (540 + a + 9)/10 = a
=> 549/10 + a/10 = a
=> 54.9 = a - 0.1a
=> 54.9 = 0.9a
=> 54.9/0.9 = a
=> 61 = a
=> 61+9 = a +9 = weight of 10th student
=> 70 = weight of 10th studenta
Answer:
- Total Students = 10
- Average of 9 Students = 60 kg
- Weight of 10th Student is 9 kh more than Average weight of all 10 Students.
- Find Weight of 10th Student.
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If we can find Average of all 10 students, then we can calculate weight of 10th student easily. (By Adding 9 kg to it) i.e. Given above.
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Average of 9 Students is 60 kg.
Weight of 10th Student exceed by 9 kg of Average of all 10 students weight.
That 9 kg is excess over Average Weight. Hence it will be distributed among all Students excluding 10th Student. Hence it will Increase Average by :
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