Math, asked by siddharth3690, 4 months ago

Out of a total of 10 students, the average weight of 9 students is 60 kg. If the Weight of the 10”‘ student is 9 kg more than the average weight of all the 10 students, then the weight of 10”‘ student would be :​
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Answered by Anonymous
7

Step-by-step explanation:

The average weight of students is 70kg.

We are required to find out the average weight of the 10 students.

Let it be x.

So, total weight of 10 students will be = ( 10 × x)kg = 10x kg.

Given that,

Average weight of 9 students = 69kg.

∴ Total weight of 9 students = (69 × 9)kg = 621 kg.

Weight of the 10th student = (Total weight of 10 students) - (Total weight of 9 students)

= (10x - 621) kg.                                          ...(1)

In the question, it is mentioned that, weight of the 10th student is also equal to 9kg more than the average weight of 10 students (which is x).

So, we represent this statement as:

Weight of 10th student = (9 + x ) kg           ...(2)

As (1) and (2), both are the same, representing the weight of 10th student, so we equate them as:

(10x - 621) = (9 + x )

⇒10x - x = 9 + 621

⇒ 9x = 630

⇒ x = 630/9 = 70

So, the average weight of the 10 students = x = 70kg.

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