Question

out of certain sum of money boys spends 2 /3 and then 1 /6 of the remainder he had rupees 25 left what had he at first​

Answer 1

Answer:

₹ 450

Step-by-step explanation:

Let the amount of money the boy initially had be = ₹ x

Amount of money the boy spent = x * 2/3 = 2x / 3

Remainder of the money = x - 2x/3 = (3x - 2x)/3 = x/3

According to the question, 1/6 of x/3 = 25

⇒1/6 * x/3 = 25

⇒x/18 = 25

⇒x = 25 * 18 = ₹ 450

∴ The boy initially had ₹ 450.

Answer 2

Answer:

90

Step-by-step explanation:

let the amount he had first be = x

on first day he spend 2/3 which is = x-2x/3 =x/3

on second day he spend remaining of 1/6 of remaining = x/3 * 1/6 = x/18  

according to question remaining amount is 25  

therefore,

x/3- x/18=25

5x/18=25

x= 25 * 18 / 5

x= 90