Question

. Out of certain sum of money Jacob spends 2/3 and
then, 1/6 of the remainder. Now he had ₹ 250 left.
What amount had he first ?​

Answer 1

Answer:

He had ₹ 900 at first.

Step-by-step explanation:

Let the sum of money of Jacob be x

Jacob spends 2/3 of x = 2x/3

Remaining = x-2x/3 = 3x-2x/3 = x/3

Again Jacob spends 1/6 of x/3 = x/18

X-(2x/3+x/18) = ₹ 250

X-(12x+x/18) = ₹ 250

X-13x/18 = ₹ 250

18x-13x/18 = ₹ 250

5x/18 = ₹ 250

5x = ₹ 250×18

X = ₹ 250×18/5

X = ₹ 50×18 = ₹ 900(answer).

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