Math, asked by animeshsankalp, 9 months ago

Out of certain sum of money Mahesh spends 2/3 on first days and 1/6 of the remainder on second day. Now he had 250 rupees left . What amount had he first ?​

Answers

Answered by knjroopa
22

Step-by-step explanation:

Given Out of certain sum of money Mahesh spends 2/3 on first days and 1/6 of the remainder on second day. Now he had 250 rupees left . What amount had he first ?

  • Let the amount Mahesh has be x
  • So he spends 2/3 of the amount = 2/3 x
  • Now remaining amount will be x – 2/3 x
  •                                            = 3x – 2x / 3
  •                                          = x/3
  • Now he spends 1/6 of the remaining amount
  • Amount spent will be 1/6 of x/3
  •                                = x/18
  • Now remaining amount will be x/3 – x/18
  •                                                = 6x – x / 18
  •                                              = 5x / 18
  • Now remaining amount is Rs 250
  • Therefore 5x / 18 = 250
  • So 5x = 250 x 18
  • Or x = Rs 900

So amount he had first is Rs 900  

Reference link will be

https://brainly.in/question/9226334

# BAL

Answered by ramakantaman198
0

900

Step-by-step explanation:

Given Out of certain sum of money Mahesh spends 2/3 on first days and 1/6 of the remainder on second day. Now he had 250 rupees left. What amount had he first ?

Let the amount Mahesh has be x

So he spends 2/3 of the amount = 2/3 x

Now remaining amount will be x -

2/3 x

3

= 3x - 2x/

= x/3

Now he spends 1/6 of the remaining amount

Amount spent will be 1/6 of x/3

= x/18

Now remaining amount will be x/3-x/18

= 6x -

x/18

= 5x/18

Now remaining amount is Rs 250

Therefore 5x / 18 = 250

• So 5x = 250 x 18

Or x = Rs 900

So amount he had first is Rs 900

Reference link will be

https://brainly.in/question/9226334

# BAL

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