Out of certain sum of money Mahesh spends 2/3 on first days and 1/6 of the remainder on second day. Now he had 250 rupees left . What amount had he first ?
Answers
Step-by-step explanation:
Given Out of certain sum of money Mahesh spends 2/3 on first days and 1/6 of the remainder on second day. Now he had 250 rupees left . What amount had he first ?
- Let the amount Mahesh has be x
- So he spends 2/3 of the amount = 2/3 x
- Now remaining amount will be x – 2/3 x
- = 3x – 2x / 3
- = x/3
- Now he spends 1/6 of the remaining amount
- Amount spent will be 1/6 of x/3
- = x/18
- Now remaining amount will be x/3 – x/18
- = 6x – x / 18
- = 5x / 18
- Now remaining amount is Rs 250
- Therefore 5x / 18 = 250
- So 5x = 250 x 18
- Or x = Rs 900
So amount he had first is Rs 900
Reference link will be
https://brainly.in/question/9226334
# BAL
900
Step-by-step explanation:
Given Out of certain sum of money Mahesh spends 2/3 on first days and 1/6 of the remainder on second day. Now he had 250 rupees left. What amount had he first ?
Let the amount Mahesh has be x
So he spends 2/3 of the amount = 2/3 x
Now remaining amount will be x -
2/3 x
3
= 3x - 2x/
= x/3
Now he spends 1/6 of the remaining amount
Amount spent will be 1/6 of x/3
= x/18
Now remaining amount will be x/3-x/18
= 6x -
x/18
= 5x/18
Now remaining amount is Rs 250
Therefore 5x / 18 = 250
• So 5x = 250 x 18
Or x = Rs 900
So amount he had first is Rs 900
Reference link will be
https://brainly.in/question/9226334
# BAL