Out of first 20 natural numbers, one number is selected at random. The probability that it is either an even number or a prime number is ?
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hope it helps.......... thank you..............
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ushamadhityaual:
you r right i have mistaken prime to be odd in a hurry
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Step-by-step explanation:
n(S) = 20
n(Even no) = 10 = n(E)
n(Prime no) = 8 = n(P)
P(E U P) = 10/20 + 8/20 - 1/20 = 17/20
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