Out of four numbers the average of first3 is 15 and that of the last three is 16 ,The last number is 19, the first is?
Answers
Answered by
0
14......................
Answered by
1
let number be a,b, c,d=19(given)
(a+b+c)/3=15
a+b+c=45
(b+c+19)/3=16
b+c=48-19=29
b+c=29
and
we know
a+ b+ c =45
a=45-(b+c)
=45-29=16 ans
a=16
hope it helps
Mark it as brainliest
(a+b+c)/3=15
a+b+c=45
(b+c+19)/3=16
b+c=48-19=29
b+c=29
and
we know
a+ b+ c =45
a=45-(b+c)
=45-29=16 ans
a=16
hope it helps
Mark it as brainliest
Similar questions