Out of given three numbers, the first is five times of the second and is two-third
of the third number. If the average of these three numbers is 36, then find the
square of the second number,
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Answer:
let the first number be x
second number =y
third number =z
x=2/3z=>z=3/2x
x=5y=>y=x/5
x+y+z/3=36
x+y+z=3*36
x+y+z=108
x+x/5+3x/2=108
27x/10=108
27x=10*108
27x=1080
x=1080/27
x=40
square of second number is (40/5)2
=(8)2
=64
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