Out of Na+, Mg+2, 0-2 and N, the pair of species
showing minimum and maximum IP would be.
(1) Nat, Mg+2
(2) Mg+2, N-3
(3) N3, Mg2 (4)O-2, N-3
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Explanation:
The term ionization potential is an older name for ionization energy. It means the amount of energy required to remove most loosely bound electron, the valence electron, of an isolated neutral gaseous atom, molecule or ion. In the given elements the number of electrons is the same i.e, 10. Hence, More is the nuclear charge more is the more is the I.P. In the given elements Mg+2 has the highest nuclear charge and N3− has the lowest nuclear charge.
Minimum IP is shown by N3−
Maximum IP is shown by Mg+2
Therefore option (3) is correct
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