out of pythagoras triplet one number is 10 .Find another number
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3,4 and 5 are pythogoras triple and n>1 ( integer) 3n,4n and 5n can also be a set of pythogoras triple...so in this case are 6,8 and 10
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pythagoras triplet =2m,m^2+1, m^2-1
let m^2+1= 10
»m^2 =9
»m =3
2m = 2*3 =6
m^2-1 = 9-1 = 8
(6,8,10)
hope it will help u:-)
let m^2+1= 10
»m^2 =9
»m =3
2m = 2*3 =6
m^2-1 = 9-1 = 8
(6,8,10)
hope it will help u:-)
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