out of six consecutive natural number, if the sum of first three is 27,the sum of other three number is what? Find.
Answers
Answered by
6
HERE IS THE SOLUTION FOR YOUR QUESTION;
◆Let the numbers be in the form of x.
So According to the question;
◆x+x+1+x+2+x+3+x+4+x+5 .......Eq"1.
From eq"1 and from the question using the details;
x+x+1+x+2=27
=>3x+3=27
=>3x=27-3
=>3x=24
=>x=8.
◆So the value of x is 8 ......eq"2◆
◆◆For the other 3 numbers◆◆
x+3+x+4+x+5 = Sum of the other 3 numbers;
=>3x+12
=> 3(8)+12. 【 Putting the value from eq"2】
=>24+12
=>36.
◆◆So The Answer Is 36◆◆
HOPE it helps
◆Let the numbers be in the form of x.
So According to the question;
◆x+x+1+x+2+x+3+x+4+x+5 .......Eq"1.
From eq"1 and from the question using the details;
x+x+1+x+2=27
=>3x+3=27
=>3x=27-3
=>3x=24
=>x=8.
◆So the value of x is 8 ......eq"2◆
◆◆For the other 3 numbers◆◆
x+3+x+4+x+5 = Sum of the other 3 numbers;
=>3x+12
=> 3(8)+12. 【 Putting the value from eq"2】
=>24+12
=>36.
◆◆So The Answer Is 36◆◆
HOPE it helps
DonDj:
If it helped u plz mark it as brainlest
Answered by
14
heya..!!!
let the consecutive no. be x ,(x +1 ) ,(x + 2),(x + 3),(x + 4),(x + 5)
=> let the three no. be x , (x + 1),(x + 2)
x + x + 1 + x + 2 = 27
=> 3x + 3 = 27
=> 3(x + 1) = 27
=> x = 9 - 1
=> x = 8
now,
the sum of other three no. be
x + 3 + x + 4 + x + 5
=> 3x + 12
=> 3×8 + 12
[ x = 8 ]
=> 24 + 12
=> 36
let the consecutive no. be x ,(x +1 ) ,(x + 2),(x + 3),(x + 4),(x + 5)
=> let the three no. be x , (x + 1),(x + 2)
x + x + 1 + x + 2 = 27
=> 3x + 3 = 27
=> 3(x + 1) = 27
=> x = 9 - 1
=> x = 8
now,
the sum of other three no. be
x + 3 + x + 4 + x + 5
=> 3x + 12
=> 3×8 + 12
[ x = 8 ]
=> 24 + 12
=> 36
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