Question

Out of the 1236 employees who work for a particular company, 748 of them work in an office. One employee is selected every month to receive a free lunch. The probability that the selected employee does not work in an office is

Answer 1

Answer: $\frac{122}{309}$ or 0.39

Step-by-step explanation:

total employees= 1236

work in an office= 748

do not work in an office= 488

Probability(do not work in an office)= $\frac{488}{1236}$ = $\frac{122}{309}$ or 0.39