Question

Out of the families having three children, a family is chosen random. Find the probability that the family has
(i) Exactly one girl
(ii) At least one girl
(iii) At most one girl

Answer 1

I hope this will help you

Answer 2

Answer:

Given : Out of the families having three children, a family is chosen random.

To find : The probability that the family has

(i) Exactly one girl

(ii) At least one girl  

(iii) At most one girl

Solution :

Total number of outcomes or possibility of the family having three children - a girl and a boy are

BBB, BBG, BGB, BGG, GBB, GBG, GGB , GGG

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

(i) Exactly one girl

Favorable outcome are :  3

Total number of outcome = 8

$\text{Probability}=\frac{3}{8}$

(ii) At least one girl

Favorable outcome are :  7

Total number of outcome = 8

$\text{Probability}=\frac{7}{8}$

(iii) At most one girl

Favorable outcome are :  3

Total number of outcome = 8

$\text{Probability}=\frac{3}{8}$