Question

Out of the given values of temperature which one is highest-(a)420K (b)130*C (c)310F (d)310K

Answer 1

we know the relation,
$\qquad\frac{K-273}{100}=\frac{C-0}{100}=\frac{F-32}{180}$

where K is temperature in Kelvin , C is temperature in degree and F is temperature in fahrenheit .

now,let's change all temperature in Kelvin for comparing.
(a) 420 K
(b) 130°C = 130+ 273 = 403K
(c) 310F => (K - 273)/100 = (310-32)/180
K -273 = 5(310 - 32)/9 = 278 × 5/9 = 154.44
K = 273 + 154.44= 427.44K
(d) 310K

here you can see highest temperature is option (c)

Answer 2

we know the relation,

\qquad\frac{K-273}{100}=\frac{C-0}{100}=\frac{F-32}{180}

100

K−273

=

100

C−0

=

180

F−32

where K is temperature in Kelvin , C is temperature in degree and F is temperature in fahrenheit .

now,let's change all temperature in Kelvin for comparing.

(a) 420 K

(b) 130°C = 130+ 273 = 403K

(c) 310F => (K - 273)/100 = (310-32)/180

K -273 = 5(310 - 32)/9 = 278 × 5/9 = 154.44

K = 273 + 154.44= 427.44K

(d) 310K

here you can see highest temperature is option (c)