Question

Out of three given numbers, the first one is twice the second and three times the third. If the average of these numbers is 88, then the difference between first and third is.

Answer 1

Answer : 96

Explaination : Let first number be x then second number = x / 2 and third number is x / 3.

Since average of the numbers is 88:

$x + \frac{x}{2} + \frac{x}{3} = 88 \times 3$

Multiply both side by 6.

$6x + 3x + 2x = 1584$

Solve it you will get x = 144

Hence,

first number is : 144

Second number is : 72

Third number is : 48

Difference between first and third number is = 96

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