Question

Out of three metals P, Q, R P is less reactive than Q and R is more reactive than P and Q both suggest an activity to arrange P, Q, R in order of decreasing reactivity

Answer 1

A.T.Q

Q>P. _1eq.

R> P, Q. _2eq.

so

R>Q>P

Answer 2

From the given conditions, it can be understood that P is less reactive than Q ,

so it can be written as: P<Q

Again, it is given that R is more reactive than P and Q so it can be placed as: P<Q<R

So, the three metals can be arranged in order of decreasing reactivity: R>Q>P

This can be proved experimentally by using displacement reaction.

In such a reaction, a more reactive metal displaces a less reactive metal in order to form a stable product, thereby proving the order of reactivity.

Also, it can be proved by checking reactivity of the metals with water, hydrochloric acid and also by heating the respective metal carbonates.