Question

out of three numbers ,the first is twice the second and is half of the third if the avarage of the three number 56 ,the three numbers in order are​

Answer 1

Answer:

let the required numbers in order be,

a,b,c.

according to question,

a=2b => b=a/2

and,. a=c/2 => c= 2a.

given that the average of the three numbers is 56, ie,

a+b+c =56

3

a+a/2 + 2a =56

3

2a+a+4a =56

3×2

7a=56×6

a=48.

thus,b=48/2=24.

and c=2×48=96

the the numbers in the order are;

48,24,96.

I hope it would help you.

thank you.

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